Institute of Prediction Technology & Forensic Mathematics (PT&FM)
President: John Wong

Institute of Prediction Technology & Forensic Mathematics (PT&FM)

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Astrological Decade Bounds Age (AP) Formula for people born in B.C.: AP=&C{R[(&C[SC:m=0, f=1]+y-1)/2]=0:{P0-m-1 (Mod 12)}x10+A[(J2-d)/3], R[(&C[SC:m=0, f=1]+y-1)/2]=1:{m-1-P0 (Mod 12)}x10+A[(d-J1)/3]}
Astrological Decade Bounds Age (AP) Formula for people born in A.D.: AP=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{P0-m-1 (Mod 12)}x10+A[(J2-d)/3], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1-P0 (Mod 12)}x10+A[(d-J1)/3]}
Explanation`Astrological Decade Bounds' is also named as `Astrological Large Bounds'. `Decade Bounds' is the focus of `Decade Fortune' because it shows the decade fortune in a zone of a person. The first `Decade Bounds' is called the `Initial Decade Bounds'. The first `Astrological Decade Bounds' is equal to the zone of `Astrological Decade Fortune' next to `Astrological Decade Fortune Origin' (UN0,ZN0) according to its direction of revolution. `Astrological Decade Bounds' moves consecutively either clockwisely or anti-clockwisely according to the `Revolution Mode' (RM) along the zones every ten years. There are altogether twelve zones. The zones recur from 0 to 11. They are integers and usually assigned to variable `X'. The `Revolution Mode' (RM) of `Decade Bounds' is a mathematical expression that can show the revolving direction of `Decade Bounds' in its `Fortune Track' (FT). There are altogether two different types of `Revolution Modes', namely `Clockwise Revolution Mode' (CRM) and `Anti-clockwise Revolution Mode' (ARM). The `Decade Bounds' of human being is revolving either clockwisely or anti-clockwisely in the `Fortune Track' (FT). It varies according to the `Sex Code' (SC) and the year of birth `y' in Gregorian calendar. For example, based on the calculation of Revolution Mode Formula `RM=R[(&C[SC:m=0, f=1]+y)/2]' for people born in A.D. or based on the calculation of Revolution Mode Formula `RM=R[(&C[SC:m=0, f=1]+y-1)/2]' for people born in B.C., if RM=0 it means that the `Revolution Mode' is clockwise. If RM=1 it means that the `Revolution Mode' is anti-clockwise. `Astrological Decade Bounds' revolves consecutively along the zones either clockwisely or anti-clockwisely for every ten years. Thus, the time interval of `Decade Bounds' is 10 years. In `PT&FM', the beginning of a year is not on 1st of January in Gregorian calendar. The beginning of a year is `Joint of February'. The critical value between two consecutive years is called `Joint of Year'. `Joint of February' is the boundary of two consecutive years. It always lies on from the 3rd to 5th day of February. In general, not for precise calculations, `Joint of February' can be regarded as the 4th day of February. If the date of birth is within the 3rd to 5th day of February, precise calculations should be carried out. That is, if the time of the date of birth is after `Joint of February', the year is `y'. If the time of the date of birth is before `Joint of February', the year is `y-1'. The time and date of `Joint of February' between two consecutive years in Gregorian calendar always change from year to year. `Joint of February' also varies according to the longitude and latitude of a place. The exact date and time of `Joint of February' of a year can be found in a Chinese lunar calendar. `SC' is the `Sex Code' of a person. The `Sex Code' of male is `M' and m=0. the `Sex Code' of female is `F' and f=1. In general, the value of `m' is assigned to `0' and the value of `f' is `1'. The `Sex Code' of transsexual is the original sex at birth. The `Sex Code' of hermaphrodite or people who are genderless could be either `M' or `F'. In this case, both sex codes should be used to check out which one is more accurate. `y' is the year of birth. `m' is the month of birth after `Joint of Month'. Usually, `Joint of Month' is from 3rd to 8th of the month. `d' is the date and time of birth reckoning in Gregorian calendar. The unit of `d' is day. The zone of `Decade Bounds' is `P0'. `AP' is the minimum age of `Decade Bounds'. `AP' is called the `Lower Bound Age' of the `Decade Bounds'. The `Upper Bound Age' is equal to `AP+9' because the time interval of `Decade Bounds' is 10 years. `J' is a conventional symbol to denote the day and time of `Joint of Month' before or after the date of birth such that `J1' is the day and time of `Joint of Month' before the date of birth and `J2' is the day and time of `Joint of Month' after the date of birth. The units of `J1' and `J2' are days. `J2-d' is the difference between the date and time of birth and the next `Joint of Month' in Gregorian calendar. The difference should be corrected to the nearest day. `d-J1' is the difference between the date and time of birth and previous `Joint of Month' in Gregorian calendar. The difference should be corrected to the nearest day. The `Astrological Decade Bounds Age' Formula for people born in A.D. is: AP=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{P0-m-1 (Mod 12)}x10+A[(J2-d)/3], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1-P0 (Mod 12)}x10+A[(d-J1)/3]}. The `Astrological Decade Bounds Age' Formula for people born in B.C. is: AP=&C{R[(&C[SC:m=0, f=1]+y-1)/2]=0:{P0-m-1 (Mod 12)}x10+A[(J2-d)/3], R[(&C[SC:m=0, f=1]+y-1)/2]=1:{m-1-P0 (Mod 12)}x10+A[(d-J1)/3]}. The `Astrological Decade Bounds Age' Formula can be simplified as follows. For `Clockwise Revolution Mode' (RM=0): AP={P0-m-1 (Mod 12)}x10+A[(J2-d)/3]. For `Anti-clockwise Revolution Mode' (RM=1): AP={m-1-P0 (Mod 12)}x10+A[(d-J1)/3]. `&C[ ]' is a conditional function of an event such that the mathematical expression after the `:' sign must be operated if the event occurs (i.e. The conditional `&C[ ]' becomes true.). `R[y/n]' is a remainder function such that it takes the remainder of `y' divided by `n'. `n' is a natural number. Natural numbers are 1,2,3,4,5,……. Zero is not a natural number. `A[n]' is an approximated integer function such that it takes the nearest whole number of `n'. `AP=(Mod 12)' is a modulated function such that if AP>11 then `AP' becomes `AP-12' and if AP<0 then `AP' becomes `AP+12'. Thus, the value range of `AP=(Mod 12)' is from 0 to 11.
ExampleAssume a male was born at 0:45 a.m. on 6th Oct.,A.D.1952. Find the minimum age (AP) when the zone of `Decade Bounds' (P0) is 4. From the given data, we know that the `Sex Code' (SC) is `M' and m=0. According to Chinese lunar calendar, we know that `Joint of Month' before the date of birth is `Joint of September' which is at 1:14 a.m. on 8th Sep.,A.D.1952. So, J1=8+(1+14/60)/24 days in September. J1=8.0513888 days in September. `Joint of Month' after the date of birth is `Joint of October' which is at 4:33 p.m. on 8th Oct.,A.D.1952. So, J2=8+(16+33/60)/24 days in October. J2=8.6895833 days in October. Since the birthday is after `Joint of Year' which is at 4:54 a.m. on 5th Feb.,A.D.1952, y=1952. Since the birthday at 0:45 a.m. on 6th Oct.,A.D.1952 is before `Joint of Month' which is at 4:33 p.m. on 8th Oct.,A.D.1952, the month of birth m=9 and d=6+45/60/24 days in October. d=6.03125 days in October. `J2-d' is the day and time difference between `Joint of October' and the date and time of birth. J2-d=8.6895833-6.03125 days. J2-d=2.6583333 days. `d-J1' is the day and time difference between the date and time of birth and `Joint of September'. d-J1=6.03125+(30-8.0513888) days. d-J1=6.03125+21.948612 days. d-J1=27.979862 days. Apply the `Astrological Decade Bounds Age' Formula for people born in A.D.. AP=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{P0-m-1 (Mod 12)}x10+A[(J2-d)/3], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1-P0 (Mod 12)}x10+A[(d-J1)/3]}. AP=&C{R[(0+1952)/2]=0:{4-9-1 (Mod 12)}x10+A[2.6583333/3], R[(0+1952)/2]=1:{9-1-4 (Mod 12)}x10+A[27.979862/3]}. AP=&C{R[1952/2]=0:{-6 (Mod 12)}x10+A[0.8861111], R[1952/2]=1:{4 (Mod 12)}x10+A[9.3266206]}. AP=&C{0=0:{12-6}x10+1, 0=1:4x10+9}. AP=&C{0=0:6x10+1, 0=1:40+9}. AP=&C{0=0:61, 0=1:49}. Since the truth value of `&C[0=0]' is true and the truth value of `&C[0=1]' is false, AP=61. Hence, the minimum age of the client is 61 when the zone of `Decade Bounds' is 4 and it ends till an age of 70. Assume a female was born at 12:23 p.m. on 4th Feb.,A.D.1925. Find the minimum age (AP) when the zone of `Decade Bounds' (P0) is 2. From the given data, we know that the `Sex Code' (SC) is `F' and f=1. According to Chinese lunar calendar, we know that `Joint of Month' before the date of birth is `Joint of January' which is at 3:54 a.m. on 6th Jan.,A.D.1925. So, J1=6+(3+54/60)/24 days in January. J1=6.1625 days in January. `Joint of Month' after the date of birth is `Joint of February' which is at 3:37 p.m. on 4th Feb.,A.D.1925. So, J2=4+(15+37/60)/24 days in February. J2=4.6506944 days in February. `Joint of February' is also `Joint of Year'. Since the birthday is before `Joint of Year' which is at 3:37 p.m. on 4th Feb.,A.D.1925, it is regarded as previous year. That is, y=1924. Since the birthday at 12:23 p.m. on 4th Feb.,A.D.1925 is before `Joint of Month' which is at 3:37 p.m. on 4th Feb.,A.D.1925, the month of birth m=1 and d=4+(12+23/60)/24 days in February. d=4.5159722 days in February. `J2-d' is the day and time difference between `Joint of February' and the date and time of birth. J2-d=4.6506944-4.5159722 days. J2-d=0.1347222 day. `d-J1' is the day and time difference between the date and time of birth and `Joint of January'. d-J1=4.5159722+(31-6.1625) days. d-J1=4.5159722+24.8375 days. d-J1=29.353472 days. Apply `Astrological Decade Bounds Age' Formula for people born in A.D.. AP=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{P0-m-1 (Mod 12)}x10+A[(J2-d)/3], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1-P0 (Mod 12)}x10+A[(d-J1)/3]}. AP=&C{R[(1+1924)/2]=0:{2-1-1 (Mod 12)}x10+A[0.1347222/3], R[(1+1924)/2]=1:{1-1-2 (Mod 12)}x10+A[29.353472/3]}. AP=&C{R[1925/2]=0:{0 (Mod 12)}x10+A[0.0449074], R[1925/2]=1:{-2 (Mod 12)}x10+A[9.7844906]}. AP=&C{1=0:0x10+0, 1=1:{12-2}x10+10}. AP=&C{1=0:0, 1=1:10x10+10}. AP=&C{1=0:0, 1=1:110}. Since the truth value of `&C[1=0]' is false and the truth value of `&C[1=1]' is true, AP=110. Hence, the minimum age of the client is 110 when the zone of `Decade Bounds' is 2 and it ends till an age of 119. Assume a male was born at 10:00 p.m. on 16th Jan.,A.D.1962. Find the minimum age (AP) when the zone of `Decade Bounds' (P0) is 10. From the given data, we know that the `Sex Code' (SC) is `M' and m=0. According to Chinese lunar calendar, we know that `Joint of Month' before the date of birth is `Joint of January' which is at 3:35 a.m. on 6th Jan.,A.D.1962. So, J1=6+(3+35/60)/24 days in January. J1=6.1493055 days in January. `Joint of Month' after the date of birth is `Joint of February' which is at 3:18 p.m. on 4th Feb.,A.D.1962. So, J2=4+(15+18/60)/24 days in February. J2=4.6375 days in February. `Joint of February' is also `Joint of Year'. Since the birthday is before `Joint of Year' which is at 3:18 p.m. on 4th Feb.,A.D.1962, it is regarded as previous year. That is, y=1961. Since the birthday at 10:00 p.m. on 16th January of A.D.1962 is after `Joint of Month' which is at 3:18 p.m. on 6th January of A.D.1962, the month of birth m=1 and d=16+22/24 days in January. d=16.916666 days in January. `J2-d' is the day and time difference between `Joint of February' and the date and time of birth. J2-d=[31-(16+22/24)]+[4+(15+18/60)/24] days. J2-d=[31-16.916666]+[4+0.6375] days. J2-d=14.083334+4.6375 days. J2-d=18.720834 days. `d-J1' is the day and time difference between the date and time of birth and `Joint of January'. d-J1=[16+22/24]-[6+(3+35/60)/24] days. d-J1=16.916666-6.1493055 days. d-J1=10.767361 days. Apply `Astrological Decade Bounds Age' Formula for people born in A.D.. AP=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{P0-m-1 (Mod 12)}x10+A[(J2-d)/3], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1-P0 (Mod 12)}x10+A[(d-J1)/3]}. AP=&C{R[(0+1961)/2]=0:{10-1-1 (Mod 12)}x10+A[18.720834/3], R[(0+1961)/2]=1:{1-1-10 (Mod 12)}x10+A[10.767361/3]}. AP=&C{R[1961/2]=0:{8 (Mod 12)}x10+A[6.240278], R[1961/2]=1:{-10 (Mod 12)}x10+A[3.5891203]}. AP=&C{1=0:8x10+6, 1=1:{12-10}x10+4}. AP=&C{1=0:86, 1=1:2x10+4}. AP=&C{1=0:86, 1=1:24}. Since the truth value of `&C[1=0]' is false and the truth value of `&C[1=1]' is true, AP=24. Hence, the minimum age of the client is 24 when the zone of `Decade Bounds' is 10 and it ends till an age of 33. An alternative method to calculate the minimum age (AP) of `Decade Bounds' is by the simplified `Decade Bounds Age' Formula. The first step is to find out the `Revolution Mode' (RM) of `Decade Fortune' of the client by the `Revolution Mode' Formula. Apply the `Revolution Mode' Formula for people born in A.D.. RM=R[(&C[SC:m=0, f=1]+y)/2]. RM=R[(0+1961)/2]. RM=R[1961/2]. RM=1. Hence, the `Revolution Mode' of `Decade Fortune' of the client is anti-clockwise. Then, apply the simplified `Astrological Decade Bounds Age' Formula for `Anti-clockwise Revolution Mode' (RM=1). AP={m-1-P0 (Mod 12)}x10+A[(d-J1)/3]. AP={1-1-10 (Mod 12)}x10+A[10.767361/3]. AP={-10 (Mod 12)}x10+A[3.5891203]. AP={12-10}x10+4. AP=2x10+4. AP=24. Hence, the minimum age of the client is 24 when the zone of `Decade Bounds' is 10 and it ends till an age of 33.

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