Institute of Prediction Technology & Forensic Mathematics (PT&FM)
President: John Wong

Institute of Prediction Technology & Forensic Mathematics (PT&FM)

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Numerological Decade Bounds (P0) Formula for birth in B.C.: P0=&C{R[(&C[SC:m=0, f=1]+y-1)/2]=0:{m+1 (Mod 12)}+I[(a-A[(J2-d)/3])/10], R[(&C[SC:m=0, f=1]+y-1)/2]=1:{m-1 (Mod 12)}-I[(a-A[(d-J1)/3])/10]} (Mod 12)
Numerological Decade Bounds (P0) Formula for birth in A.D.: P0=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{m+1 (Mod 12)}+I[(a-A[(J2-d)/3])/10], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1 (Mod 12)}-I[(a-A[(d-J1)/3])/10]} (Mod 12)
Explanation`Numerological Decade Bounds' is also named as `Numerological Large Bounds'. `Numerological Decade Bounds' is the focus of `Numerological Decade Fortune' because it shows the decade fortune in a zone of a person. The first `Numerological Decade Bounds' is called the `Initial Decade Bounds'. The first `Numerological Decade Bounds' is equal to the zone of `Numerological Decade Fortune' next to `Numerological Decade Fortune Origin' (UN0,ZN0) according to its direction of revolution. The `Numerological Decade Bounds' moves consecutively either clockwisely or anti-clockwisely according to the `Revolution Mode' (RM) along the zones every ten years. There are altogether twelve zones. The zones recur from 0 to 11. They are integers and usually assigned to variable `X'. The `Revolution Mode' (RM) of `Numerological Decade Bounds' is a mathematical expression that can show the revolving direction of `Numerological Decade Bounds' in its `Fortune Track' (FT). There are altogether two different types of `Revolution Modes', namely `Clockwise Revolution Mode' (CRM) and `Anti-clockwise Revolution Mode' (ARM). The `Numerological Decade Bounds' of human being is revolving either clockwisely or anti-clockwisely in the `Fortune Track' (FT). It varies according to the `Sex Code' (SC) and the year of birth `y' in Gregorian calendar. For example, based on the calculation of Revolution Mode Formula `RM=R[(&C[SC:m=0, f=1]+y)/2]' for people born in A.D. or based on the calculation of Revolution Mode Formula `RM=R[(&C[SC:m=0, f=1]+y-1)/2]' for people born in B.C., if RM=0 it means that the `Revolution Mode' is clockwise. If RM=1 it means that the `Revolution Mode' is anti-clockwise. The standard general form of `Numerological Decade Bounds' Formula for people born in `y' A.D. is: P0=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{m+1 (Mod 12)}+I[(a-A[(J2-d)/3])/10], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1 (Mod 12)}-I[(a-A[(d-J1)/3])/10]} (Mod 12). The standard general form of `Numerological Decade Bounds' Formula for people born in `y' B.C. is: P0=&C{R[(&C[SC:m=0, f=1]+y-1)/2]=0:{m+1 (Mod 12)}+I[(a-A[(J2-d)/3])/10], R[(&C[SC:m=0, f=1]+y-1)/2]=1:{m-1 (Mod 12)}-I[(a-A[(d-J1)/3])/10]} (Mod 12). `y' is the year of birth after `Joint of Year' in Gregorian calendar. Usually, `Joint of Year' is on 4th of February. `Joint of Year' is same as `Joint of February'. `m' is the month of birth after `Joint of Month'. Usually, `Joint of Month' is from 3rd to 8th of the month. `J' is a conventional symbol to denote the day and time of `Joint of Month' before or after the date of birth such that `J1' is the day and time of `Joint of Month' before the date of birth and `J2' is the day and time of `Joint of Month' after the date of birth. The units of `J1' and `J2' are days. `d' is the day and time of birth. The unit of `d' is in day. `J2-d' is the difference between the date and time of birth and the next `Joint of Month' in Gregorian calendar. The difference should be corrected to the nearest day. `d-J1' is the difference between the date and time of birth and previous `Joint of Month' in Gregorian calendar. The difference should be corrected to the nearest day. `a' is the age of the person in `Numerological Decade Bounds'. `SC' is the `Sex Code' of a person. The `Sex Code' of male is `M' and m=0. The `Sex code' of female is `F' and f=1. In general, the value of `m' is assigned to `0' and the value of `f' is `1'. The `Sex Code' of transsexual is the original sex at birth. In this case, both sex codes should be used to check out which one is more accurate. The `Numerological Decade Bounds' moves consecutively either clockwisely or anti-clockwisely along the zones every ten years. Thus, the time interval of `Numerological Decade Bounds' is 10 years. If we let the zone of `Numerological Decade Bounds' at age `a' be `P0', `Minimum Age Decade Fortune' be 'e', then for people born in A.D. is: e=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:A[(J2-d)/3], R[(&C[SC:m=0, f=1]+y)/2]=1:A[(d-J1)/3]}. For people born in B.C. is: e=&C{R[(&C[SC:m=0, f=1]+y-1)/2]=0:A[(J2-d)/3], R[(&C[SC:m=0, f=1]+y-1)/2]=1:A[(d-J1)/3]}. If the value of `J' is unknown, let J=6 for approximate calculation. The maximum deviation in age for approximate calculation is 1. If the birthday is between 3rd to 8th, approximate calculation cannot be used. The calculation must use precise value of `J'. If one's age is less than `Minimum Age Decade Fortune', i.e. `a' is less than `e', one is not qualified to have a `Decade Fortune'. So, one has no `Numerological Decade Bounds' at that moment. The simplified form of `Numerological Decade Bounds' Formula for people born in `y' A.D. is: If a>e or a=e, P0=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{m+1 (Mod 12)}+I[(a-e)/10], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1 (Mod 12)}-I[(a-e)/10]} (Mod 12). The simplified form of `Numerological Decade Bounds' Formula for people born in `y' B.C. is: If a>e or a=e, P0=&C{R[(&C[SC:m=0, f=1]+y-1)/2]=0:{m+1 (Mod 12)}+I[(a-e)/10], R[(&C[SC:m=0, f=1]+y-1)/2]=1:{m-1 (Mod 12)}-I[(a-e)/10]} (Mod 12). `&C[ ]' is a conditional function of an event such that the mathematical expression after the `:' sign must be operated if the event occurs (i.e. The conditional `&C[ ]' becomes true.). `R[y/n]' is a remainder function such that it takes the remainder of `y' divided by `n'. `n' is a natural number. Natural numbers are 1,2,3,4,5,……. Zero is not a natural number. `I[n]' is an integer function such that it takes the integral part of number `n' without rounding up the number. `A[n]' is an approximated integer function such that it takes the nearest whole number of `n'. `P0=(Mod 12)' is a modulated function such that if P0>11 then `P0' becomes `P0-12' and if P0<0 then `P0' becomes `P0+12'. Thus, the value range of `P0=(Mod 12)' is from 0 to 11.
ExampleAssume a male was born at 10:00 p.m. on 16th Jan.,A.D.1962. Find the zone of `Numerological Decade Bounds' (P0) in A.D.2012. From the given data, we know that the `Sex Code' (SC) is `m' and m=0. According to Chinese lunar calendar, we know that `Joint of Month' before the date of birth is `Joint of January' which is at 3:35 a.m. on 6th Jan.,A.D.1962. So, J1=6+(3+35/60)/24 days in January. J1=6.1493055 days in January. `Joint of Month' after the date of birth is `Joint of February' which is at 3:18 p.m. on 4th Feb.,A.D.1962. So, J2=4+(15+18/60)/24 days in February. J2=4.6375 days in February. `Joint of February' is also `Joint of Year'. Since the birthday is before `Joint of Year' which is at 3:18 p.m. on 4th Feb.,A.D.1962, it is regarded as previous year. That is, y=1961. The age of the person in A.D.2012 is a=2012-1961. a=51. Since the birthday at 10:00 p.m. on 16th January of A.D.1962 is after `Joint of Month' which is at 3:18 p.m. on 6th January of A.D.1962, the month of birth m=1 and d=16+22/24 days in January. d=16.916666 days in January. `J2-d' is the day and time difference between `Joint of February' and the date and time of birth. J2-d=[31-(16+22/24)]+[4+(15+18/60)/24] days. J2-d=[31-16.916666]+[4+0.6375] days. J2-d=14.083334+4.6375 days. J2-d=18.720834 days. `d-J1' is the day and time difference between the date and time of birth and `Joint of January'. d-J1=[16+22/24]-[6+(3+35/60)/24] days. d-J1=16.916666-6.1493055 days. d-J1=10.767361 days. Apply the standard general form of `Numerological Decade Bounds' Formula for people born in A.D.. P0=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{m+1 (Mod 12)}+I[(a-A[(J2-d)/3])/10], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1 (Mod 12)}-I[(a-A[(d-J1)/3])/10]} (Mod 12). The zone of `Numerological Decade Bounds' (P0) is P0=&C{R[(0+1961)/2]=0:{1+1 (Mod 12)}+I[(51-A[(14.083334+4.6375)/3])/10], R[(0+1961)/2]=1:{1-1 (Mod 12)}-I[(51-A[(16.9166-6.1493)/3])/10]} (Mod 12). P0=&C{R[1961/2]=0:{2 (Mod 12)}+I[(51-A[18.720834/3])/10], R[1961/2]=1:{0 (Mod 12)}-I[(51-A[10.7673/3])/10]} (Mod 12). P0=&C{1=0:2+I[(51-A[6.240278])/10], 1=1:0-I[(51-A[3.5891])/10]} (Mod 12). P0=&C{1=0:2+I[(51-6)/10], 1=1:0-I[(51-4)/10]} (Mod 12). P0=&C{1=0:2+I[45/10], 1=1:-I[47/10]} (Mod 12). P0=&C{1=0:2+I[4.5], 1=1:-I[4.7]} (Mod 12). P0=&C{1=0:2+4, 1=1:-4} (Mod 12). P0=&C{1=0:6, 1=1:-4} (Mod 12). Since the truth value of `&C[1=0]' is false and the truth value of `&C[1=1]' is true, P0= -4 (Mod 12). P0=12-4. P0=8. Assume a male was born at 10:35 a.m. on 27th Sep.,A.D.1952. Find the zone of `Numerological Decade Bounds' (P0) in A.D.2007. From the given data, we know that the `Sex Code' (SC) is `m' and m=0. According to Chinese lunar calendar, we know that `Joint of Month' before the date of birth is `Joint of September' which is at 1:14 a.m. on 8th Sep.,A.D.1952. So, J1=8+(1+14/60)/24 days in September. J1=8.0513888 days in September. `Joint of Month' after the date of birth is `Joint of October' which is at 4:33 p.m. on 8th Oct.,A.D.1952. So, J2=8+(16+33/60)/24 days in October. J2=8.6895833 days in October. Since the birthday is after `Joint of Year' which is at 4:54 a.m. on 5th Feb.,A.D.1952, y=1952. The age of the person in A.D.2007 is a=2007-1952. a=55. Since the birthday at 10:35 a.m. on 27th Sep.,A.D.1952 is after `Joint of Month' which is at 1:14 a.m. on 8th Sep.,A.D.1952, the month of birth m=9 and d=27+(10+35/60)/24 days in September. d=27.440972 days in September. `J2-d' is the day and time difference between `Joint of October' and the date and time of birth. J2-d=8+(16+33/60)/24+{30-[27+(10+35/60)/24]} days. J2-d=8.6895833+{30-27.440972} days. J2-d=11.248611 days. `d-J1' is the day and time difference between the date and time of birth and `Joint of September'. d-J1=27+(10+35/60)/24-[8+(1+14/60)/24] days. d-J1=27.440972-8.0513888 days. d-J1=19.389584 days. The `Minimum Age Numerological Decade Fortune' for people born in A.D. is e=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:A[(J2-d)/3], R[(&C[SC:m=0, f=1]+y)/2]=1:A[(d-J1)/3]}. e=&C{R[(0+1952)/2]=0:A[11.248611/3], R[(0+1952)/2]=1:A[19.389584/3]}. e=&C{0=0:A[3.749537], 0=1:A[6.4631946]}. e=&C{0=0:4, 0=1:6}. Since the truth value of `&C[0=0]' is true and the truth value of `&C[0=1]' is false, e=4. That is a>e. Apply the `Numerological Decade Bounds' Formula for people born in A.D.. If a>e or a=e, P0=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{m+1 (Mod 12)}+I[(a-e)/10], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1 (Mod 12)}-I[(a-e)/10]} (Mod 12). The zone of `Numerological Decade Bounds' (P0) is P0=&C{R[(0+1952)/2]=0:{9+1 (Mod 12)}+I[(55-4)/10], R[(0+1952)/2]=1:{9-1 (Mod 12)}-I[(55-4)/10]} (Mod 12). P0=&C{R[1952/2]=0:{10 (Mod 12)}+I[51/10], R[1952/2]=1:{8 (Mod 12)}-I[51/10]} (Mod 12). P0=&C{0=0:{10 (Mod 12)}+I[5.1], 0=1:{8 (Mod 12)}-I[5.1} (Mod 12). P0=&C{0=0:10+5, 0=1:8-5} (Mod 12). P0=&C{0=0:15, 0=1:3} (Mod 12). Since the truth value of `&C[0=0]' is true and the truth value of `&C[0=1]' is false, P0=15 (Mod 12). P0=15-12. P0=3. Assume a female was born at 12:23 p.m. on 20th Apr.,A.D.1926. Find the zone of `Numerological Decade Bounds' (P0) in A.D.1997. From the given data, we know that the `Sex Code' (SC) is `f' and f=1. According to Chinese lunar calendar, we know that `Joint of Month' before the date of birth is `Joint of April' which is at 9:19 p.m. on 5th Apr.,A.D.1926. So, J1=5+(21+19/60)/24] days in April. J1=5.8881944 days in April. `Joint of Month' after the date of birth is `Joint of May' which is at 3:09 p.m. on 6th May,A.D.1926. So, J2=6+(15+9/60)/24 days in May. J2=6.63125 days in May. Since the birthday is after `Joint of Year' which is at 9:39 p.m. on 4th Feb.,A.D.1926, `Year of Birth' y=1926. The age of the person in A.D.1997 is a=1997-1926. a=71. Since the birthday at 12:23 p.m. on 20th Apr.,A.D.1926 is after `Joint of Month' which is at 9:19 p.m. on 5th Apr.,A.D.1926, the month of birth m=4 and d=20+(12+23/60)/24 days in April. d=20.515972 days in April. `J2-d' is the day and time difference between `Joint of May' and the date and time of birth. J2-d=6+(15+9/60)/24+{30-[20+(12+23/60)/24]}. J2-d=6.63125+{30-20.515972}. J2-d=16.115278. `d-J1' is the day and time difference between the date and time of birth and `Joint of April'. d-J1=20+(12+23/60)/24-[5+(21+19/60)/24] days. d-J1=20.515972-5.8881944 days. d-J1=14.627778 days. The `Minimum Age Decade Fortune' for people born in A.D. is e=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:A[(J2-d)/3], R[(&C[SC:m=0, f=1]+y)/2]=1:A[(d-J1)/3]}. e=&C{R[(1+1926)/2]=0:A[16.115278/3], R[(1+1926)/2]=1:A[14.627778/3]}. e=&C{R[1927/2]=0:A[5.3717593], R[(1927/2]=1:A[4.875926]}. e=&C{1=0:5, 1=1:5}. Since the truth value of `&C[1=0]' is false and the truth value of `&C[1=1]' is true, e=5. That is, a>e. Apply the `Numerological Decade Bounds' Formula for people born in A.D.. If a>e or a=e, P0=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{m+1 (Mod 12)}+I[(a-e)/10], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1 (Mod 12)}-I[(a-e)/10]} (Mod 12). The zone of `Numerological Decade Bounds' (P0) is P0=&C{R[(1+1926)/2]=0:{4+1 (Mod 12)}+I[(71-5)/10], R[(1+1926)/2]=1:{4-1 (Mod 12)}-I[(71-5)/10]} (Mod 12). P0=&C{R[1927/2]=0:{5 (Mod 12)}+I[66/10], R[1927/2]=1:{3 (Mod 12)}-I[66/10]} (Mod 12). P0=&C{1=0:5+I[6.6], 1=1:3-I[6.6]} (Mod 12). P0=&C{1=0:5+6, 1=1:3-6} (Mod 12). P0=&C{1=0:11, 1=1:-3} (Mod 12)。 Since the truth value of `&C[1=0]' is false and the truth value of `&C[1=1]' is true, P0= -3 (Mod 12). P0=12-3. P0=9.

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