Institute of Prediction Technology & Forensic Mathematics (PT&FM)
President: John Wong

Institute of Prediction Technology & Forensic Mathematics (PT&FM)

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Analysis of Sequence Codes of Second Fortune Co-ordinates (G6,C6) and Numerology (N)
N=01:(1,0)N=02:(2,1)N=03:(3,2)N=04:(4,3)N=05:(5,4)N=06:(6,5)N=07:(7,6)N=08:(8,7)N=09:(9,8)N=10:(10,9)
N=11:(1,10)N=12:(2,11)N=13:(3,0)N=14:(4,1)N=15:(5,2)N=16:(6,3)N=17:(7,4)N=18:(8,5)N=19:(9,6)N=20:(10,7)
N=21:(1,8)N=22:(2,9)N=23:(3,10)N=24:(4,11)N=25:(5,0)N=26:(6,1)N=27:(7,2)N=28:(8,3)N=29:(9,4)N=30:(10,5)
N=31:(1,6)N=32:(2,7)N=33:(3,8)N=34:(4,9)N=35:(5,10)N=36:(6,11)N=37:(7,0)N=38:(8,1)N=39:(9,2)N=40:(10,3)
N=41:(1,4)N=42:(2,5)N=43:(3,6)N=44:(4,7)N=45:(5,8)N=46:(6,9)N=47:(7,10)N=48:(8,11)N=49:(9,0)N=50:(10,1)
N=51:(1,2)N=52:(2,3)N=53:(3,4)N=54:(4,5)N=55:(5,6)N=56:(6,7)N=57:(7,8)N=58:(8,9)N=59:(9,10)N=60:(10,11)


Analysis of Second Fortune (G6=G, C6=C) Formula
50-seconds time interval (s) in 10 minutes0-5050-100100-150150-200200-250250-300300-350350-400400-450450-500500-550550-600
Value of vertical axis of 50-seconds time interval:
C=I[s/50]
C=0C=1C=2C=3C=4C=5C=6C=7C=8C=9C=10C=11
Value of horizontal axis of Minute (GM) :
GM=1
G=1G=2G=3G=4G=5G=6G=7G=8G=9G=10G=1G=2
GM=2G=3G=4G=5G=6G=7G=8G=9G=10G=1G=2G=3G=4
GM=3G=5G=6G=7G=8G=9G=10G=1G=2G=3G=4G=5G=6
GM=4G=7G=8G=9G=10G=1G=2G=3G=4G=5G=6G=7G=8
GM=5G=9G=10G=1G=2G=3G=4G=5G=6G=7G=8G=9G=10
GM=6G=1G=2G=3G=4G=5G=6G=7G=8G=9G=10G=1G=2
GM=7G=3G=4G=5G=6G=7G=8G=9G=10G=1G=2G=3G=4
GM=8G=5G=6G=7G=8G=9G=10G=1G=2G=3G=4G=5G=6
GM=9G=7G=8G=9G=10G=1G=2G=3G=4G=5G=6G=7G=8
GM=10G=9G=10G=1G=2G=3G=4G=5G=6G=7G=8G=9G=10

Simplified Second Fortune (G6=G, C6=C) Formula
50-seconds time interval (s) in 10 minutes0-5050-100100-150150-200200-250250-300300-350350-400400-450450-500500-550550-600
Value of vertical axis of 50-seconds time interval:
C=I[s/50]
C=0C=1C=2C=3C=4C=5C=6C=7C=8C=9C=10C=11
Value of horizontal axis of Minute (GM) :
GM=1 or 6
G=1G=2G=3G=4G=5G=6G=7G=8G=9G=10G=1G=2
GH=2 or 7G=3G=4G=5G=6G=7G=8G=9G=10G=1G=2G=3G=4
GH=3 or 8G=5G=6G=7G=8G=9G=10G=1G=2G=3G=4G=5G=6
GH=4 or 9G=7G=8G=9G=10G=1G=2G=3G=4G=5G=6G=7G=8
GH=5 or 10G=9G=10G=1G=2G=3G=4G=5G=6G=7G=8G=9G=10

Second Fortune Formula: U=Z-1+2xGM (Mod 10) & Z=I[{{t (Mod 7200)} (Mod 600)}/50]
ExplanationSince a pair of Minute Fortune Co-ordinates represent ten minutes and 10 minutes is equal to 600 seconds, each pair of Second Fortune Co-ordinates represent 50 seconds. In general, the `Second Fortune Co-ordinates' are expressed as (G6,C6). `G6' is the Stem of Second Code (Second Stem) and `C6' is the Root of Second Code (Second Root). The time interval of Stem and Root of Second Code is 50 seconds. As there are twelve values in `C6' and there are 600 seconds (10 minutes) in a Minute Code, a value of `C6' stands for 50 seconds. The value of `C6' shifts to the next after passing the time at 0 second, 50 seconds or a multiple of 50 seconds. The value of `C6' can be calculated directly from time `t' expressed in 24-hour system. But, for finding out the value of `G6', the `G5' value of `Minute Fortune Co-ordinates' (G5,C5) of ten minutes must be calculated first. Assume the `Minute Fortune Co-ordinates' are (GM,CM) and the `Second Fortune Co-ordinates' are (U,Z). `t' is the time counting in seconds reckoning in 24-hour system. The `Second Fortune Formula' is `U=Z-1+2xGM (Mod 10) & Z=I[{{t (Mod 7200)} (Mod 600)}/50]'. No matter male or female, the `Second Fortune Co-ordinates' (G6,C6) always spin clockwise. The `Second Fortune Co-ordinates' start to move from the `Origin of Second Fortune Co-ordinates' at (UN6,ZN6) to the next Second Fortune Co-ordinates' (G6,C6) after 50 seconds. They oscillate in a loop of 60 and they are expressed as (G6,C6), where `G6' and `C6' are integers. For `G6' values in modulus of ten, 1 is `A', 2 is `B', 3 is `C', 4 is `D', 5 is `E', 6 is `F', 7 is `G', 8 is `H', 9 is `I', 10 is `J'. So, (1,0)=A0, (2,1)=B1, (3,2)=C2, and so on. For `C6' values in modulus of twelve, 0 is `A', 1 is `B', 2 is `C', 3 is `D', 4 is `E', 5 is `F', 6 is `G', 7 is `H', 8 is `I', 9 is `J', 10 is `K', 11 is `L'. So, (1,0)=1A, (2,1)=2B, (3,2)=3C, and so on. For all in terms of alphabets, (1,0)=AA, (2,1)=BB, (3,2)=CC, and so on. They are called `Fortune Codes'. The `Fortune Code' of an interval of 50 seconds is called the `Second Fortune Code' or `Second Code'. `I[n]' is an integer function such that it takes the integral part of number `n' without rounding up the number. `U=(Mod 10)' is a special modulated function such that the smallest value of it is 1 and the largest value of it is 10. If U>10 then `U' becomes `U-10' and if U<1 then `U' becomes `U+10'. Thus, the value range of `U=(Mod 10)' is from 1 to 10. `Z=(Mod 7200)' is a modulated function such that if Z>7199 then `Z' becomes `Z-7200' and if Z<0 then `Z' becomes `Z+7200'. Thus, the value range of `Z=(Mod 7200)' is from 0 to 7199. `Z=(Mod 600)' is a modulated function such that if Z>599 then `Z' becomes `Z-600' and if Z<0 then `Z' becomes `Z+600'. Thus, the value range of `Z=(Mod 600)' is from 0 to 599.
ExampleAssume to find the `Second Fortune Co-ordinates' (G6,C6) of the time at 3:07:39 a.m. on 15th June of 2011. Firstly, find out the value of `G5' by applying the `Minute Fortune Formula'. `G5=3'. Thus, `GM=3'. Next, calculate the value of `t'. t=3x3600+7x60+39. t=11259. Then, apply the `Second Fortune Formula', `U=Z-1+2xGM (Mod 10) & Z=I[{{t (Mod 7200)} (Mod 600)}/50]'. Find the value of `Z' first. Z=I[{{11259 (Mod 7200)} (Mod 600)}/50]. Z=I[{11259-7200 (Mod 600)}/50]. Z=I[{4059 (Mod 600)}/50]. Z=I[{4059-600x6}/50]. Z=I[459/50]. Z=I[9.18]. Z=9. U=9-1+2x3 (Mod 10). U=14 (Mod 10). U=14-10. U=4. Hence, the `Second Fortune Co-ordinates' (G6,C6) of time at 3:07:39 a.m. on 15th June of 2011 is (4,9). The `Second Code' is `34',`D9', `4J', `DJ' or `DIM-YAU'. If the time is 11:44:42 p.m. on 20th December of 1995, find the `Second Fortune Co-ordinates' (G6,C6). Firstly, find out the value of `G5' by applying the `Minute Fortune Formula'. `G5=3'. Thus, `GM=3'. Next, calculate the value of `t'. t=23x3600+44x60+42. t=85482. Then, apply the `Second Fortune Formula', `U=Z-1+2xGM (Mod 10) & Z=I[{{t (Mod 7200)} (Mod 600)}/50]'. Find the value of `Z' first. Z=I[{{85482 (Mod 7200)} (Mod 600)}/50]. Z=I[{85482-7200x11 (Mod 600)}/50]. Z=I[{6282 (Mod 600)}/50]. Z=I[{6282-600x10}/50]. Z=I[282/50)]. Z=I[5.64]. Z=5. U=5-1+2x3 (Mod 10), U=10 (Mod 10), U=10. Hence, the `Second Fortune Co-ordinates' (G6,C6) of time at 11:44:42 p.m. on 20th December of 1995 is (10,5). The `Second Code' is `30', `J5', `10F', `JF' or `QUI-CHJ'.