| Explanation | Asume the origin of `Numerological Small Fortune Co-ordinates' is at (Uo,Zo), where `Uo' and `Zo' are integers. The origin of `Numerological Small Fortune' is the starting point of one's fortune from year to year. `Numerological Small Fortune' of people is either spinning clockwisely or anti-clockwisely based on `Numerological Small Fortune Spin Mode' following the order of `Fortune Co-ordinates'. It starts to move from `Numerological Small Fortune Origin' at (Uo,Zo) to the next `Fortune Co-ordinates' on a yearly base. The destiny of human beings in a year is controlled by two `Fortune Tracks' (FT). They are `Annual Fortune Track' (AFT) and `Year Fortune Track' (YFT). The `Annual Fortune Track' (AFT) is usually called `Small Fortune Track' (SFT). `Numerological Small Fortune Spin Mode' (SM) is a mathematical expression that can show the spinning direction of `Numerological Small Fortune' in `Small Fortune Track' (SFT). Note that `Small Fortune Spin Mode' is different from `Year Fortune Spin Mode'. The `Year Fortune Spin Mode' is always clockwise. There is no `Anti-clockwise Spin Mode' for `Year Fortune' but there does exist `Anti-clockwise Spin Mode' for `Small Fortune' (Annual Fortune). Do not confused by them. There are altogether two different types of `Spin Modes' (SM), namely `Clockwise Spin Mode' (CSM) and `Anti-clockwise Spin Mode' (ASM). It varies according to the `Sex Code' (SC) of a person and the year of birth `y' in Gregorian calendar. `Numerological Small Fortune Spin Mode' Formula for people born in B.C. is SM=R[(&C[SC:m=0, f=1]+y-1)/2]. `Numerological Small Fortune Spin Mode' Formula for people born in A.D. is SM=R[(&C[SC:m=0, f=1]+y)/2]. Despite of people born in A.D. or B.C. and based on calculation of `Numerological Small Fortune Spin Mode' Formula, SM=0 means the spin mode is clockwise. If SM=1, it means the spin mode is anti-clockwise. Numerological Small Fortune recurs in 60 `Fortune Co-ordinates' expressed as `(U,Z)' where `U' and `Z' are integers. It starts to move from `Numerological Small Fortune Origin' (Uo,Zo) to next `Fortune Co-ordinates' (U,Z) on a yearly base. People who are classified as `SM=0' will increase the value of `Fortune Co-ordinates' clockwisely and people who are classified as `SM=1' will decrease the value of `Fortune Co-ordinates' anti-clockwisely. The `Sex Code' of male is `M' and m=0. The `Sex Code' of female is `F' and f=1. In general, the value of `m' is assigned to `0' and the value of `f' is `1'. The `Sex Code' of transsexual is the original sex at birth. The `Sex Code' of hermaphrodite (H), people have neutral sex (N) or genderless (N) could be either `M' or `F'. In this case, both sex codes should be used to check out which one is more accurate. `Numerological Small Fortune' (NSF) is a special type of annual fortune of a person. It is different from `Year Fortune' (YF). `Numerological Small Fortune' begins neither from the first day of year in Gregorian calendar nor the first day of the first month in Chinese lunar calendar. It begins from `Joint of February' and ends before `Joint of February' next year in Gregorian calendar. Normally, different people have different `Small Fortunes' in a year. In general, `Numerological Small Fortune Co-ordinates' are expressed as (U,Z). `U' is called the `Stem' of `Numerological Small Fortune' and `Z' is called the `Root' of `Numerological Small Fortune'. The standard general form of `Numerological Small Fortune' Formula for people in B.C. is U=&C{R[(&C[SC:m=0, f=1]+y-1)/2]=0:{A[h/2] (Mod 12)}-1+2x{UD &C{A[h/2]=12:+1}}+a, R[(&C[SC:m=0, f=1]+y-1)/2]=1:{A[h/2] (Mod 12)}-1+2x{UD &C{A[h/2]=12:+1}}-a} (Mod 10) & Z=&C{R[(&C[SC:m=0, f=1]+y-1)/2]=0:A[h/2]+a, R[(&C[SC:m=0, f=1]+y-1)/2]=1:A[h/2]-a} (Mod 12). The standard general form of `Small Fortune' Formula for people in A.D. is U=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{A[h/2] (Mod 12)}-1+2x{UD &C{A[h/2]=12:+1}}+a, R[(&C[SC:m=0, f=1]+y)/2]=1:{A[h/2] (Mod 12)}-1+2x{UD &C{A[h/2]=12:+1}}-a} (Mod 10) & Z=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:A[h/2]+a, R[(&C[SC:m=0, f=1]+y)/2]=1:A[h/2]-a} (Mod 12). `y' is the year of birth after `Joint of Year'. If the birthday is before `Joint of Year', the year of birth `y' is regarded as previous year. `Joint of Year' is same as `Joint of February'. Usually, it is on 4th February. `a' is the age of a person in the current year. `UD' is the stem of the day and `h' is the time counting in hours in 24-hour system when a person was born. The value of `Z' can be calculated directly from time `h' expressed in 24-hour system. But, for finding out the value `U' of `Numerological Small Fortune', the value `UD' of `Day Fortune Co-ordinates' (UD,ZD) of the day at birth must be calculated by `Day Fortune Origin' Formula first. `Numerological Small Fortune Spin Mode' is denoted by `SM'. `SM=0' means `Numerological Small Fortune' spins clockwisely. `SM=1' means `Numerological Small Fortune' spins anti-clockwisely. Regarding to different spin modes, `Numerological Small Fortune' Formula can be simplified as follows. If SM=0, then U={A[h/2] (Mod 12)}-1+2x{UD &C{A[h/2]=12:+1}}+a (Mod 10) & Z=A[h/2]+a (Mod 12). If SM=1, then U={A[h/2] (Mod 12)}-1+2x{UD &C{A[h/2]=12:+1}}-a (Mod 10) & Z=A[h/2]-a (Mod 12). The `Time Interval' between two consecutive `Numerological Small Fortune Co-ordinates' is 1 year. If the location of `Numerological Small Fortune Co-ordinates' is at (X,Y), the position of `Numerological Small Fortune Co-ordinates' is at (U,Z) after `y' years. `Numerological Small Fortune' Formula can be further simplified as follows. U=&C[SM=0:X+y, SM=1:X-y] (Mod 10) & Z=&C[SM=0:Y+y, SM=1:Y-y] (Mod 12). `R[y/n]' is a remainder function such that it takes the remainder of `y' divided by `n'. `n' is a natural number. Natural numbers are 1,2,3,4,5,……. Zero is not a natural number. `A[n]' is an approximated integer function such that it takes the nearest whole number of `n'. `&C[ ]' is a conditional function of an event such that the mathematical expression after the `:' sign must be operated if the event occurs (i.e. The conditional `&C[ ]' becomes true.). `U=(Mod 10)' is a special modulated function such that the smallest value of it is 1 and the largest value of it is 10. If U>10 then `U' becomes `U-10' and if U<1 then `U' becomes `U+10'. Thus, the value range of `U=(Mod 10)' is from 1 to 10. `Z=(Mod 12)' is a modulated function such that the smallest value of it is 0 and the largest value of it is 11. If Z>11 then `Z' becomes `Z-12' and if `Z' is less than 0 then `Z' becomes `Z+12'. Thus, the value range of `Z=(Mod 12)' is from 0 to 11. |
| Example | Assume a male was born at 0:45 a.m. on 6th October of 1952. Find the Stem (U) and Root (Z) of `Numerological Small Fortune' (U,Z) at 10:45 a.m. on 17th August of 1986. Also, find the `Fortune Co-ordinates' and `Numerological Small Fortune Code'. The `Sex Code' of male is `m' and m=0. Since the birthday is after `Joint of Year' which is at 4:54 a.m. on 5th February of 1952, y=1952. The exact age is a=1985-1952 and a=33 because the day of event which is at 10:45 a.m. on 17th August of 1986 is before the birthday in 1986. Firstly, find out the stem of day (UD) by applying the `Day Fortune Origin' Formula and UD=2. Next, calculate the value of `h'. h=0+45/60. h=0.75 . Then, apply `Numerological Small Fortune' Formula for people born in A.D., `U=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{A[h/2] (Mod 12)}-1+2x{UD &C{A[h/2]=12:+1}}+a, R[(&C[SC:m=0, f=1]+y)/2]=1:{A[h/2] (Mod 12)}-1+2x{UD &C{A[h/2]=12:+1}}-a} (Mod 10) & Z=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:A[h/2]+a, R[(&C[SC:m=0, f=1]+y)/2]=1:A[h/2]-a} (Mod 12)' to find the value of `Z'. Z=&C{R[(0+1952)/2]=0:A[0.75/2]+33, R[(0+1952)/2]=1:A[0.75/2]-33} (Mod 12). Z=&C{R[1952/2]=0:A[0.375]+33, R[1952/2]=1:A[0.375]-33} (Mod 12). Z=&C{0=0:0+33, 0=1:0-33} (Mod 12). Z=&C{0=0:33, 0=1:-33} (Mod 12). Since the truth value of `&C[0=0]' is true and the truth value of `&C[0=1]' is false, Z=33 (Mod 12). Z=33-12x2. Z=9. Hence, U=&C{R[(0+1952)/2]=0:{A[0.75/2] (Mod 12)}-1+2x{2 &C{A[0.75/2]=12:+1}}+33, R[(0+1952)/2]=1:{A[0.75/2] (Mod 12)}-1+2x{2 &C{A[0.75/2]=12:+1}}-33} (Mod 10). U=&C{R[1952/2]=0:{A[0.375] (Mod 12)}-1+2x{2 &C{A[0.375]=12:+1}}+33, R[1952/2]=1:{A[0.375] (Mod 12)}-1+2x{2 &C{A[0.375]=12:+1}}-33} (Mod 10). U=&C{0=0:{0 (Mod 12)}-1+2x{2 &C{0=12:+1}}+33, 0=1:{0 (Mod 12)}-1+2x{2 &C{0=12:+1}}-33} (Mod 10). U=&C{0=0:0-1+2x{2 &C{0=12:+1}}+33, 0=1:0-1+2x{2 &C{0=12:+1}}-33} (Mod 10). U=&C{0=0:-1+2x{2 &C{0=12:+1}}+33, 0=1:-1+2x{2 &C{0=12:+1}}-33} (Mod 10). Since the truth value of `&C[0=12]' is false, the mathematical expression `+1' after the sign `:' is not operated. U=&C{0=0:-1+2x2+33, 0=1:-1+2x2-33} (Mod 10). U=&C{0=0:36, 0=1:-30} (Mod 10). Since the truth value of `&C[0=0]' is true and the truth value of `&C[0=1]' is false, U=36 (Mod 10). U=36-10x3. U=6. The Stem (U) of `Numerological Small Fortune' (U,Z) of the client at 10:45 a.m. on 17th August of 1986 is `F' because `F' is the sixth alphabet and the `Root' is 9. So, `Numerological Small Fortune Co-ordinates' are (6,9). `Numerological Small Fortune Code' is `46', `F9', `6J', `FJ' or `GAI-YAU'. Assume a female was born at 1:06 a.m. on 12th August of 1959 in Hong Kong. Find the Stem (U) and Root (Z) of `Numerological Small Fortune' (U,Z) at 10:45 a.m. on 17th August of 1986. Also, find the `Fortune Co-ordinates' and `Numerological Small Fortune' Code. The `Sex Code' of female is `F' and f=1. The place of birth of the client in Hong Kong is 114 degrees 10 minutes east of longitude. The time is delayed by 23 minutes and 30 seconds from its standard time zone which is the time of 120 degrees east of longitude. Thus, the real time when the client was born is at 0:42:30 on 12th August of 1959. Since the birthday is after `Joint of Year' which is at 9:43 p.m. on 4th February of 1959, y=1959. The exact age is a=1986-1959 and a=27 because the day of event which is at 10:45 a.m. on 17th August of 1986 is after the birthday in 1986. Firstly, find out the stem of day (UD) by applying the `Day Fortune Origin' Formula and UD=3. Next, calculate the value of `h'. h=0+42/60+30/3600. h=0.7+0.00833 . h=0.70833 . Then, apply `Numerological Small Fortune' Formula for people born in A.D., `U=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{A[h/2] (Mod 12)}-1+2x{UD &C{A[h/2]=12:+1}}+a, R[(&C[SC:m=0, f=1]+y)/2]=1:{A[h/2] (Mod 12)}-1+2x{UD &C{A[h/2]=12:+1}}-a} (Mod 10) & Z=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:A[h/2]+a, R[(&C[SC:m=0, f=1]+y)/2]=1:A[h/2]-a} (Mod 12)' to find the value of `Z'. Z=&C{R[(1+1959)/2]=0:A[0.70833/2]+27, R[(1+1959)/2]=1:A[0.70833/2]-27} (Mod 12). Z=&C{R[1960/2]=0:A[0.374165]+27, R[1960/2]=1:A[0.374165]-27} (Mod 12). Z=&C{0=0:0+27, 0=1:0-27} (Mod 12). Z=&C{0=0:27, 0=1:-27} (Mod 12). Since the truth value of `&C[0=0]' is true and the truth value of `&C[0=1]' is false, Z=27 (Mod 12). Z=27-12x2. Z=3. Hence, U=&C{R[(1+1959)/2]=0:{A[0.70833/2] (Mod 12)}-1+2x{3 &C{A[0.70833/2]=12:+1}}+27, R[(1+1959)/2]=1:{A[0.70833/2] (Mod 12)}-1+2x{3 &C{A[0.70833/2]=12:+1}}-27} (Mod 10). U=&C{R[1960/2]=0:{A[0.374165] (Mod 12)}-1+2x{3 &C{A[0.374165]=12:+1}}+27, R[1960/2]=1:{A[0.374165] (Mod 12)}-1+2x{3 &C{A[0.374165]=12:+1}}-27} (Mod 10). U=&C{0=0:{0 (Mod 12)}-1+2x{3 &C{0=12:+1}}+27, 0=1:{0 (Mod 12)}-1+2x{3 &C{0=12:+1}}-27} (Mod 10). U=&C{0=0:0-1+2x{3 &C{0=12:+1}}+27, 0=1:0-1+2x{3 &C{0=12:+1}}-27} (Mod 10). U=&C{0=0:-1+2x{3 &C{0=12:+1}}+27, 0=1:-1+2x{3 &C{0=12:+1}}-27} (Mod 10). Since the truth value of `&C[0=12]' is false, the mathematical expression `+1' after the sign `:' is not operated. U=&C{0=0:-1+2x3+27, 0=1:-1+2x3-27} (Mod 10). U=&C{0=0:32, 0=1:-22} (Mod 10). Since the truth value of `&C[0=0]' is true and the truth value of `&C[0=1]' is false, U=32 (Mod 10). U=32-10x3. U=2. The Stem (U) of `Numerological Small Fortune' (U,Z) of the client at 10:45 a.m. on 17th August of 1986 is `B' because `B' is second alphabet and the `Root' is 3. So, `Numerological Small Fortune Co-ordinates' are (2,3). `Numerological Small Fortune Code' is `52', `B3', `2D', `BD' or `EUT-MOU'. |
