Institute of Prediction Technology & Forensic Mathematics (PT&FM)
President: John Wong

Institute of Prediction Technology & Forensic Mathematics (PT&FM)

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Analysis of Sequence Codes of Hour Co-ordinates (U,Z) and Numerology (N)
N=01:(1,0)N=02:(2,1)N=03:(3,2)N=04:(4,3)N=05:(5,4)N=06:(6,5)N=07:(7,6)N=08:(8,7)N=09:(9,8)N=10:(10,9) N=11:(1,10)N=12:(2,11)N=13:(3,0)N=14:(4,1)N=15:(5,2)N=16:(6,3)N=17:(7,4)N=18:(8,5)N=19:(9,6)N=20:(10,7) N=21:(1,8)N=22:(2,9)N=23:(3,10)N=24:(4,11)N=25:(5,0)N=26:(6,1)N=27:(7,2)N=28:(8,3)N=29:(9,4)N=30:(10,5) N=31:(1,6)N=32:(2,7)N=33:(3,8)N=34:(4,9)N=35:(5,10)N=36:(6,11)N=37:(7,0)N=38:(8,1)N=39:(9,2)N=40:(10,3) N=41:(1,4)N=42:(2,5)N=43:(3,6)N=44:(4,7)N=45:(5,8)N=46:(6,9)N=47:(7,10)N=48:(8,11)N=49:(9,0)N=50:(10,1) N=51:(1,2)N=52:(2,3)N=53:(3,4)N=54:(4,5)N=55:(5,6)N=56:(6,7)N=57:(7,8)N=58:(8,9)N=59:(9,10)N=60:(10,11)

The `U-coordinate' of Hour Code on X-axis

The `Z-coordinate' of Hour Code on Y-axis

Analysis of 60 Hour Codes (HC): Table #1

Analysis of 60 Hour Codes (HC): Table #2

Analysis of 60 Hour Codes (HC): Table #3
01: AA02: BB03: CC04: DD05: EE06: FF07: GG08: HH09: II10: JJ
11: AK12: BL13: CA14: DB15: EC16: FD17: GE18: HF19: IG20: JH
21: AI22: BJ23: CK24: DL25: EA26: FB27: GC28: HD29: IE30: JF
31: AG32: BH33: CI34: DJ35: EK36: FL37: GA38: HB39: IC40: JD
41: AE42: BF43: CG44: DH45: EI46: FJ47: GK48: HL49: IA50: JB
51: AC52: BD53: CE54: DF55: EG56: FH57: GI58: HJ59: IK60: JL

Analysis of 60 Hour Codes (HC): Table #4

The Hour Set Formula (HS): h=2Z
ExplanationAssume `y' is the solar year after `Joint of February', roughly on 4th of February in Gregorian calendar, and `m' is the solar month after `Joint of Month'. If the date is before `Joint of Month', the value of `m' is equal to previous month. If the `Year Code' (YC) and `Month Code' (MC) of two dates are same, the `Day Code' (DC) is (UD,ZD), `d' is the number of days counting from 1st of January of the year (y). `d1' is the value of `d' calculated from the value of Stem of Day (UD) and `d2' is the value of `d' calculated from the value of Root of Day (ZD). If d1=d2 and the months (m) are same, the two dates belong to same `Time Set'. The Day Set Formulae are: d1=UD+5-365(y-1)-I[(y-1)/4]+I[(y-1)/100]-I[(y-1)/400]+I[(y-1)/3225] (Mod 10) & d2=ZD+10-365(y-1)-I[(y-1)/4]+I[(y-1)/100]-I[(y-1)/400]+I[(y-1)/3225] (Mod 12). `d=(Mod 10)' is a special modulated function such that the smallest value of it is 1 and the largest value of it is 10. If d>10 then `d' becomes `d-10' and if d<1 then `d' becomes `d+10'. Thus, the value range of `d=(Mod 10)' is from 1 to 10. `d=(Mod 12)' is another modulated function such that if d>12 then `d' becomes `d-12' and if d<1 then `d' becomes `d+12'. Thus, the value range of `d=(Mod 12)' is from 1 to 12. The `Hour Set Formula' is used to find the time in hours from an `Hour Code' (HC). The `Hour Code' is expressed in the form of `Hour Co-ordinates' (U,Z). If `h' is the time reckoning in a 24-hour system of a date, the Hour Set Formula is: h=2Z. In `Prediction Technology and Forensic Mathematics' (PT&FM), `Time Set' is a set of time which has same `Time Codes'. If the precision of time in the `Time Set' is two hours, it is an `Hour Set'. The time in `Hour Set' is sexagesimal. The `Time Codes' of months, days and times in the `Set' are same but years are different. So, they are classified as a set. For example, the `Time Codes' (TC) of 3:05a.m. on 30th June, 1951 and 4:59a.m. on 15th June, 2011 are regarded as identical because they are in same 2-hour interval. TC=H3A6H1G2. The Numerology (N) is N=28313827. These two data of time belong to same `Time Set' because they are in same 2-hour interval. In the `Hour Code' (U,Z), `U' is called the `Stem' of the `Hour Code' and `Z' is called the `Root' of the `Hour Code' where `U' and `Z' are integers. The value of `U' shows the alphabetical order of the letter that it represents. For values of `U' which stands for time interval of a couple of hours (2 hours), 1 is `A', 2 is `B', 3 is `C', 4 is `D', 5 is `E', 6 is `F', 7 is `G', 8 is `H', 9 is `I', 10 is `J'. So, (1,0)=A0, (2,1)=B1, (3,2)=C2, and so on. The value of `Z' is the Root of Hour Code. It stands for time interval of a couple of hours. For `Z' values, 0 is `A', 1 is `B', 2 is `C', 3 is `D', 4 is `E', 5 is `F', 6 is `G', 7 is `H', 8 is `I', 9 is `J', 10 is `K', 11 is `L'. So, (1,0)=1A, (2,1)=2B, (3,2)=3C, and so on. For all in terms of alphabets, (1,0)=AA, (2,1)=BB, (3,2)=CC, and so on. The value of `Z' also shows the location and direction of a couple of hours. It is equal to the Zone Number (Z) in the space of the universe.
ExampleIf the Time Code (TC) of a time strap in a specified year y=1958 is `E10F7D11H11', find the time in Gregorian calendar. The Time Code (TC) is `E10F7D11H11' means the Numerology (N) is `35562448'. The Year Code is YC=E10 and it can represent y=1958. The Month Code is MC=F7 and `7' is the Root of Month Code, `m'. So, m=7. It means the 7th month in Gregorian calendar. That is July. The Day Code (DC) is `D11'. The Stem (UD) of Day Code is UD=4 because `D' is the fourth letter in alphabetical order. The Root (ZD) of Day Code is ZD=11. Firstly, find out the date which lies in the month (m) as well as `d1' and `d2' both satisfies the `Day Set Formulae'. The date is 9th July, 1958. Then, appy the `Hour Set Formula' to find the time of the `Time Code'. The `Hour Code' (HC) is `H11'. The Stem (U) of Hour Code is U=8 because `H' is the eighth letter in alphabetical order. The Root (Z) of Hour Code is Z=11. Apply the `Hour Set Formula'. h=2Z, h=2x11. h=22. The time is 10:00 p.m.. In history, a great earthquake that caused a huge tsunami in Lituya Bay of Alaska, U.S.A., occurred at 10:15:12 p.m. on 9th July,1958. By this approach, we can forecast wars of massive destructions and natural disasters by finding the dates and time of all logical combinations of bad codes of year, month, day and time related to the timeons of `Yeu',`Tor',`Jit',`Pik' & `Psu'. The probability of such events that will occur is very great.