| Explanation | The origin of `Decade Fortune Co-ordinates' is at (UN0,ZN0), where `UN0' and `ZN0' are integers. The origin of `Decade Fortune' is the starting point of one's `Decade Fortune'. The `Decade Fortune' is revolving around in the space either clockwisely or anti-clockwisely. The `Decade Fortune' of human being is revolving either clockwisely or anti-clockwisely in the `Fortune Track' (FT). It varies according to the `Sex Code' (SC) and the year of birth `y' in Gregorian calendar. For example, based on the calculation of Revolution Mode Formula `RM=R[(&C[SC:m=0, f=1]+y)/2]' for people born in A.D. or based on the calculation of Revolution Mode Formula `RM=R[(&C[SC:m=0, f=1]+y-1)/2]' for people born in B.C., if RM=0 it means that the `Revolution Mode' is clockwise. If RM=1 it means that the `Revolution Mode' is anti-clockwise. The `Fortune Co-ordinates' start to shift from the origin at (UN0,ZN0) to the next `Fortune Co-ordinates' on a 10-yearly base. The `Decade Fortune' recurs in 60 `Fortune Co-ordinates' expressed as `(G0,C0)' where `G0' and `C0' are integers. The standard general form of `Numerological Decade Fortune' Formula for people born in `y' A.D. is: G0=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:3+{m+1 (Mod 12)}&C[m+1<2:+2]+2x{R[y/10] (Mod 5)}+I[(a-A[(J2-d)/3])/10], R[(&C[SC:m=0, f=1]+y)/2]=1:3+{m-1 (Mod 12)}&C[m-1<2:+2]+2x{R[y/10] (Mod 5)}-I[(a-A[(d-J1)/3])/10]} (Mod 10) & C0=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{m+1 (Mod 12)}+I[(a-A[(J2-d)/3])/10], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1 (Mod 12)}-I[(a-A[(d-J1)/3])/10]} (Mod 12). `Numerological Decade Fortune' Formula can be simplified as follows. For `Clockwise Revolution Mode' (RM=0): G0=3+{m+1 (Mod 12)}&C[m+1<2:+2]+2x{R[y/10] (Mod 5)}+I[(a-A[(J2-d)/3])/10] (Mod 10) & C0={m+1 (Mod 12)}+I[(a-A[(J2-d)/3])/10] (Mod 12). For `Anti-clockwise Revolution Mode' (RM=1): G0=3+{m-1 (Mod 12)}&C[m-1<2:+2]+2x{R[y/10] (Mod 5)}-I[(a-A[(d-J1)/3])/10] (Mod 10) & C0={m-1 (Mod 12)}-I[(a-A[(d-J1)/3])/10] (Mod 12). `y' is the year of birth in A.D. after `Joint of Year' in Gregorian calendar. Usually, `Joint of Year' is on 4th of February. `Joint of Year' is same as `Joint of February'. `m' is the month of birth after `Joint of Month'. Usually, `Joint of Month' is from 3rd to 8th of the month in Gregorian calendar. `J' is a conventional symbol to denote the day and time of `Joint of Month' before or after the date of birth such that `J1' is the day and time of `Joint of Month' before the date of birth and `J2' is the day and time of `Joint of Month' after the date of birth. The units of `J1' and `J2' are days. `d' is the day and time at birth. `J2-d' is the difference between the date and time of birth and the next `Joint of Month' in Gregorian calendar. The difference should be corrected to the nearest day. `d-J1' is the difference between the date and time of birth and previous `Joint of Month' in Gregorian calendar. The difference should be corrected to the nearest day. `a' is the age of the person in `Decade Bounds'. `SC' is the `Sex Code' of a person. The `Sex Code' of male is `M' and m=0. The `Sex code' of female is `F' and f=1. In general, the value of `m' is assigned to `0' and the value of `f' is `1'. The `Sex Code' of transsexual is the original sex at birth. The `Sex Code' of hermaphrodite (H), people have neutral sex (N) or genderless (N) could be either `M' or `F'. In this case, both sex codes should be used to check out which one is more accurate. The `Time Interval' between two consecutive `Decade Fortune Co-ordinates' is 10 years. Hence, `n=10', where `n' is the time interval between two consecutive `Decade Fortune Co-ordinates' in years. If the position of `Decade Fortune Co-ordinates' is at (X,Y), then the `Decade Fortune Co-ordinates' are at (G0,C0) after `y' years. The simplified form of `Fortune Co-ordinates' Formula: G0=&C{RM=0:G0=X+I[y/n] (Mod 10), RM=1:G0=X-I[y/n] (Mod 10)} & C0=&C{RM=0:C0=Y+I[y/n] (Mod 12), RM=1:C0=Y-I[y/n] (Mod 12)}. It can be further simplified as follows. For `Clockwise Revolution Mode' (RM=0): G0=X+I[y/10] (Mod 10) & C0=Y+I[y/10] (Mod 12). For `Anti-clockwise Revolution Mode' (RM=1): G0=X-I[y/10] (Mod 10) & C0=Y-I[y/10] (Mod 12). The standard general form of `Numerological Decade Fortune' Formula for people born in `y' B.C. is: G0=&C{R[(&C[SC:m=0, f=1]+y-1)/2]=0:3+{m+1 (Mod 12)}&C[m+1<2:+2]-2x{R[(1-y)/10] (Mod 5)}+I[(a-A[(J2-d)/3])/10], R[(&C[SC:m=0, f=1]+y-1)/2]=1:3+{m-1 (Mod 12)}&C[m-1<2:+2]-2x{R[(1-y)/10] (Mod 5)}-I[(a-A[(d-J1)/3])/10]} (Mod 10) & C0=&C{R[(&C[SC:m=0, f=1]+y-1)/2]=0:{m+1 (Mod 12)}+I[(a-A[(J2-d)/3])/10], R[(&C[SC:m=0, f=1]+y-1)/2]=1:{m-1 (Mod 12)}-I[(a-A[(d-J1)/3])/10]} (Mod 12). Note that the `Revolution Mode' Formula for people born in `y' B.C. is different from people born in `y' A.D.. The `Revolution Mode' Formula for people born in `y' B.C. is `RM=R[(&C[SC:m=0, f=1]+y-1)/2]'. `&C[ ]' is a conditional function of an event such that the mathematical expression after the `:' sign must be operated if the event occurs (i.e. The conditional `&C[ ]' becomes true.). `I[n]' is an integer function such that it takes the integral part of number `n' without rounding up the number. `A[n]' is an approximated integer function such that it takes the nearest whole number of `n'. `G0=(Mod 10)' is a special modulated function such that the smallest value of it is 1 and the largest value of it is 10. If G0>10 then `G0' becomes `G0-10' and if G0<1 then `G0' becomes `G0+10'. Thus, the value range of `G0=(Mod 10)' is from 1 to 10. `C0=(Mod 12)' is a modulated function such that if C0>11 then `C0' becomes `C0-12' and if C0<0 then `C0' becomes `C0+12'. Thus, the value range of `C0=(Mod 12)' is from 0 to 11. |
| Example | Assume a male was born at 10:00 p.m. on 16th Jan.,A.D.1962. Find the `Stem', `Root' and `Decade Fortune Code' (Big Fortune Code) of his `Decade Fortune' in A.D.2012. From the given data, we know that the `Sex Code' (SC) is `M' and m=0. According to Chinese lunar calendar, we know that `Joint of Month' before the date of birth is `Joint of January' which is at 3:35 a.m. on 6th Jan.,A.D.1962. So, J1=6+(3+35/60)/24 days in January. J1=6.1493 days in January. `Joint of Month' after the date of birth is `Joint of February' which is at 3:18 p.m. on 4th Feb.,A.D.1962. So, J2=4+(15+18/60)/24 days in February. J2=4.6375 days in February. `Joint of February' is also `Joint of Year'. Since the birthday is before `Joint of Year' which is at 3:18 p.m. on 4th Feb.,A.D.1962, it is regarded as previous year. That is, y=1961. The age of the person in A.D.2012 is a=2012-1961. a=51. Since the birthday at 10:00 p.m. on 16th January of A.D.1962 is after `Joint of Month' which is at 3:18 p.m. on 6th January of A.D.1962, the month of birth m=1 and d=16+22/24 days in January. d=16.9166 days in January. `J2-d' is the day and time difference between `Joint of February' and the date and time of birth. J2-d=[31-(16+22/24)]+[4+(15+18/60)/24] days. J2-d=[31-16.916666]+[4+0.6375] days. J2-d=14.083334+4.6375 days. J2-d=18.720834 days. `d-J1' is the day and time difference between the date and time of birth and `Joint of January'. d-J1=[16+22/24]-[6+(3+35/60)/24] days. d-J1=16.916666-6.1493055 days. d-J1=10.767361 days. Apply the standard general form of `Numerological Decade Fortune' Formula for people born in A.D.. G0=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:3+{m+1 (Mod 12)}&C[m+1<2:+2]+2x{R[y/10] (Mod 5)}+I[(a-A[(J2-d)/3])/10], R[(&C[SC:m=0, f=1]+y)/2]=1:3+{m-1 (Mod 12)}&C[m-1<2:+2]+2x{R[y/10] (Mod 5)}-I[(a-A[(d-J1)/3])/10]} (Mod 10) & C0=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{m+1 (Mod 12)}+I[(a-A[(J2-d)/3])/10], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1 (Mod 12)}-I[(a-A[(d-J1)/3])/10]} (Mod 12). G0=&C{R[(0+1961)/2]=0:3+{1+1 (Mod 12)}&C[1+1<2:+2]+2x{R[1961/10] (Mod 5)}+I[(51-A[18.720834/3])/10], R[(0+1961)/2]=1:3+{1-1 (Mod 12)}&C[1-1<2:+2]+2x{R[1961/10] (Mod 5)}-I[(51-A[10.767361/3])/10]} (Mod 10) & C0=&C{R[(0+1961)/2]=0:{1+1 (Mod 12)}+I[(51-A[18.720834/3])/10], R[(0+1961)/2]=1:{1-1 (Mod 12)}-I[(51-A[10.767361/3])/10]} (Mod 12). G0=&C{R[1961/2]=0:3+{2 (Mod 12)}&C[2<2:+2]+2x{1 (Mod 5)}+I[(51-A[6.240278])/10], R[1961/2]=1:3+{0 (Mod 12)}&C[0<2:+2]+2x{1 (Mod 5)}-I[(51-A[3.5891203])/10]} (Mod 10) & C0=&C{R[1961/2]=0:{2 (Mod 12)}+I[(51-A[6.240278])/10], R[1961/2]=1:{0 (Mod 12)}-I[(51-A[3.5891203])/10]} (Mod 12). G0=&C{1=0:3+2+2x1+I[(51-6)/10], 1=1:3+0+2+2x1-I[(51-4)/10]} (Mod 10) & C0=&C{1=0:2+I[(51-6)/10], 1=1:0-I[(51-4)/10]} (Mod 12). G0=&C{1=0:7+I[45/10], 1=1:7-I[45/10]} (Mod 10) & C0=&C{1=0:2+I[45/10], 1=1:0-I[45/10]} (Mod 12). G0=&C{1=0:7+I[4.5], 1=1:7-I[4.5]} (Mod 10) & C0=&C{1=0:2+I[4.5], 1=1:0-I[4.5]} (Mod 12). G0=&C{1=0:7+4, 1=1:7-4} (Mod 10) & C0=&C{1=0:2+4, 1=1:0-4} (Mod 12). G0=&C{1=0:11, 1=1:3} (Mod 10) & C0=&C{1=0:6, 1=1:-4} (Mod 12). Since the truth value of `&C[1=0]' is false and the truth value of `&C[1=1]' is true, G0=3 (Mod 10) and C0= -4 (Mod 12). G0=3 and C0=12-4. C0=8. `G0=3' stands for the `Stem' (G0) of the `Decade Fortune' of the client in A.D.2012 is `C' because `C' is the 3rd alphabet. The `Root' (C0) of `Decade Fortune' is 8. So, the `Decade Fortune Co-ordinates' are (3,8). The `Big Fortune Code' is `33', `C8', `3I', `CI' or `BIM-SAN'. An alternative method is to find the `Revolution Mode' (RM) of the `Decade Fortune' first. RM=R[(&C[SC:m=0, f=1]+y)/2]. RM=R[(0+1961)/2]. RM=R[1961/2]. RM=1. The `Revolution Mode' of the `Decade Fortune' is anti-clockwise. Then, apply the simplified form of `Numerological Decade Fortune' Formula for people born in A.D. for anti-clockwise `Revolution Mode' (RM=1). G0=3+{m-1 (Mod 12)}&C[m-1<2:+2]+2x{R[y/10] (Mod 5)}-I[(a-A[(d-J1)/3])/10] (Mod 10) & C0={m-1 (Mod 12)}-I[(a-A[(d-J1)/3])/10] (Mod 12). G0=3+{1-1 (Mod 12)}&C[1-1<2:+2]+2x{R[1961/10] (Mod 5)}-I[(51-A[(16.9166-6.1493)/3])/10] (Mod 10) & C0={1-1 (Mod 12)}-I[(51-A[(16.9166-6.1493)/3])/10] (Mod 12). G0=3+{0 (Mod 12)}&C[0<2:+2]+2x{1 (Mod 5)}-I[(51-A[10.7673/3])/10] (Mod 10) & C0={0 (Mod 12)}-I[(51-A[10.7673/3])/10] (Mod 12). G0=3+0+2+2x1-I[(51-A[3.5891])/10] (Mod 10) & C0=0-I[(51-A[3.5891])/10] (Mod 12). G0=5+2-I[(51-4)/10] (Mod 10) & C0= -I[(51-4)/10] (Mod 12). G0=7-I[47/10] (Mod 10) & C0= -I[47/10] (Mod 12). G0=7-I[4.7] (Mod 10) & C0= -I[4.7] (Mod 12). G0=7-4 (Mod 10) & C0= -4 (Mod 12). G0=3 (Mod 10) & C0=12-4. G0=3 & C0=8. The `Stem' of the `Decade Fortune' of the client in A.D.2012 is `C' because `C' is the 3rd alphabet and the `Root' is 8. So, the `Decade Fortune Code' (Big Fortune Code) is `C8'. Assume a female was born at 12:23 p.m. on 4th February of A.D.1925. Find the `Stem', `Root' and `Decade Fortune Code' (Big Fortune Code) of her `Decade Fortune' in A.D.1997. From the given data, we know that the `Sex Code' (SC) is `f' and f=1. According to Chinese lunar calendar, we know that `Joint of Month' before the date of birth is `Joint of January' which is at 3:54 a.m. on 6th Jan.,A.D.1925. So, J1=6+(3+54/60)/24 days in January. J1=6.1625 days in January. `Joint of Month' after the date of birth is `Joint of February' which is at 3:37 p.m. on 4th Feb.,A.D.1925. So, J2=4+(15+37/60)/24 days in February. J2=4.6506944 days in February. `Joint of February' is also `Joint of Year'. Since the birthday is before `Joint of Year' which is at 3:37 p.m. on 4th Feb.,A.D.1925, it is regarded as previous year. That is, y=1924. The age of the person in A.D.1997 is a=1997-1924. a=73. Since the birthday at 12:23 p.m. on 4th February of A.D.1925 is before `Joint of Month' which is at 3:37 p.m. on 4th February of A.D.1925, the month of birth m=1. Since the time of birth is at 12:23 p.m. on 4th February of A.D.1925, d=4+(12+23/60)/24 days in February. d=4.5159722 days in February. `J2-d' is the day and time difference between `Joint of February' and the date and time of birth. J2-d=4.6506944-4.5159722 days. J2-d=0.1347222 day. `d-J1' is the day and time difference between the date and time of birth and `Joint of January'. d-J1=4.5159722+(31-6.1625) days. d-J1=4.5159722+24.8375 days. d-J1=29.353472 days. Apply the standard general form of `Numerological Decade Fortune' Formula for people born in A.D.. G0=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:3+{m+1 (Mod 12)}&C[m+1<2:+2]+2x{R[y/10] (Mod 5)}+I[(a-A[(J2-d)/3])/10], R[(&C[SC:m=0, f=1]+y)/2]=1:3+{m-1 (Mod 12)}&C[m-1<2:+2]+2x{R[y/10] (Mod 5)}-I[(a-A[(d-J1)/3])/10]} (Mod 10) & C0=&C{R[(&C[SC:m=0, f=1]+y)/2]=0:{m+1 (Mod 12)}+I[(a-A[(J2-d)/3])/10], R[(&C[SC:m=0, f=1]+y)/2]=1:{m-1 (Mod 12)}-I[(a-A[(d-J1)/3])/10]} (Mod 12). G0=&C{R[(1+1924)/2]=0:3+{1+1 (Mod 12)}&C[1+1<2:+2]+2x{R[1924/10] (Mod 5)}+I[(73-A[0.1347222/3])/10], R[(1+1924)/2]=1:3+{1-1 (Mod 12)}&C[1-1<2:+2]+2x{R[1924/10] (Mod 5)}-I[(73-A[29.353472/3])/10]} (Mod 10) & C0=&C{R[(1+1924)/2]=0:{1+1 (Mod 12)}+I[(73-A[0.1347222/3])/10], R[(1+1924)/2]=1:{1-1 (Mod 12)}-I[(73-A[29.353472/3])/10]} (Mod 12). G0=&C{R[1925/2]=0:3+{2 (Mod 12)}&C[2<2:+2]+2x{4 (Mod 5)}+I[(73-A[0.0449074])/10], R[1925/2]=1:3+{0 (Mod 12)}&C[0<2:+2]+2x{4 (Mod 5)}-I[(73-A[9.7844906])/10]} (Mod 10) & C0=&C{R[1925/2]=0:{2 (Mod 12)}+I[(73-A[0.0449074])/10], R[1925/2]=1:{0 (Mod 12)}-I[(73-A[9.7844906])/10]} (Mod 12). G0=&C{1=0:3+2&C[2<2:+2]+2x4+I[(73-0)/10], 1=1:3+0&C[0<2:+2]+2x4-I[(73-10)/10]} (Mod 10) & C0=&C{1=0:2+I[(73-0)/10], 1=1:0-I[(73-10)/10]} (Mod 12). G0=&C{1=0:3+2+8+I[73/10], 1=1:3+0+2+8-I[63/10]} (Mod 10) & C0=&C{1=0:2+I[73/10], 1=1:-I[63/10]} (Mod 12). G0=&C{1=0:13+I[7.3], 1=1:13-I[6.3]} (Mod 10) & C0=&C{1=0:2+I[7.3], 1=1:-I[6.3]} (Mod 12). G0=&C{1=0:13+7, 1=1:13-6} (Mod 10) & C0=&C{1=0:2+7, 1=1:-6} (Mod 12). G0=&C{1=0:20, 1=1:7} (Mod 10) & C0=&C{1=0:9, 1=1:-6} (Mod 12). Since the truth value of `&C[1=0]' is false and the truth value of `&C[1=1]' is true, G0=7 (Mod 10) and C0= -6 (Mod 12). G0=7 and C0=12-6. C0=6. The `Stem' of the `Decade Fortune' of the client in A.D.1997 is `G' because `G' is the 7th alphabet and the `Root' is 6. So, the `Decade Fortune Co-ordinates' are (7,6). The `Big Fortune Code' is `07', `G6', `7G', `GG' or `GEN-NGG'. An alternative method is to find the `Revolution Mode' (RM) of the `Decade Fortune' first. RM=R[(&C[SC:m=0, f=1]+y)/2]. RM=R[(1+1924)/2]. RM=R[1925/2]. RM=1. The `Revolution Mode' of the `Decade Fortune' is anti-clockwise. Then, apply the simplified form of `Numerological Decade Fortune' Formula for people born in A.D. for anti-clockwise `Revolution Mode' (RM=1). G0=3+{m-1 (Mod 12)}&C[m-1<2:+2]+2x{R[y/10] (Mod 5)}-I[(a-A[(d-J1)/3])/10] (Mod 10) & C0={m-1 (Mod 12)}-I[(a-A[(d-J1)/3])/10] (Mod 12). G0=3+{1-1 (Mod 12)}&C[1-1<2:+2]+2x{R[1924/10] (Mod 5)}-I[(73-A[29.353472/3])/10] (Mod 10) & C0={1-1 (Mod 12)}-I[(73-A[29.353472/3])/10] (Mod 12). G0=3+{0 (Mod 12)}&C[0<2:+2]+2x{4 (Mod 5)}-I[(73-A[9.7844906])/10] (Mod 10) & C0={0 (Mod 12)}-I[(73-A[9.7844906])/10] (Mod 12). G0=3+0+2+2x4-I[(73-10)/10] (Mod 10) & C0=0-I[(73-10)/10] (Mod 12). G0=13-I[63/10] (Mod 10) & C0= -I[63/10] (Mod 12). G0=13-I[6.3] (Mod 10) & C0= -I[6.3] (Mod 12). G0=13-6 (Mod 10) & C0= -6 (Mod 12). G0=7 (Mod 10) & C0=12-6. G0=7 & C0=6. The `Stem' of the `Decade Fortune' of the client in A.D.1997 is `G' because `G' is the 7th alphabet and the `Root' is 6. So, the `Decade Fortune Code' (Big Fortune Code) is `G6'. Assume the present `Decade Fortune Co-ordinates' (X,Y) are (2,9) and the `Revolution Mode' is clockwise (i.e. RM=0). Find the `Decade Fortune Co-ordinates' (G0,C0) of 16 years later (i.e. y=16). Apply the simplified Decade Fortune Formula. G0=X+I[y/10] (Mod 10) & C0=Y+I[y/10] (Mod 12). The values of `G0' and `C0' of the new `Decade Fortune Co-ordinates' (G0,C0) after `y' years are: G0=2+I[16/10] (Mod 10) & C0=9+I[16/10] (Mod 12). G0=2+I[1.6] (Mod 10) & C0=9+I[1.6] (Mod 12). G0=2+1 (Mod 10) & C0=9+1 (Mod 12). G0=3 (Mod 10) & C0=10 (Mod 12). G0=3 & C0=10. Hence, after counting 16 years clockwisely, the `Decade Fortune' will move from `Co-ordinates' (2,9) with a value of the `Sequence Code of Decade Fortune Co-ordinates' of `22' to `Co-ordinates' (3,10) with a new value of the `Sequence Code of Decade Fortune Co-ordinates' of `23'. Thus, the value of the `Sequence Code of Decade Fortune Co-ordinates' is changed from `22' to `23'. Assume the present `Decade Fortune Co-ordinates' (X,Y) are (8,1) and the `Revolution Mode' is anti-clockwise (i.e. RM=1). Find the `Decade Fortune Co-ordinates' (G0,C0) of 42 years later (i.e. y=42). Apply the simplified Decade Fortune Formula. G0=X-I[y/10] (Mod 10) & C0=Y-I[y/10] (Mod 12). The values of `G0' and `C0' of the new `Decade Fortune Co-ordinates' (G0,C0) after `y' years are: G0=8-I[42/10] (Mod 10) & C0=1-I[42/10] (Mod 12). G0=8-I[4.2] (Mod 10) & C0=1-I[4.2] (Mod 12). G0=8-4 (Mod 10) & C0=1-4 (Mod 12). G0=4 (Mod 10) & C0= -3 (Mod 12). G0=4 & C0=12-3. C0=9. Hence, after counting 42 years anti-clockwisely, the `Decade Fortune' will move from `Co-ordinates' (8,1) with a value of the `Sequence Code of Decade Fortune Co-ordinates' of `38' to `Co-ordinates' (4,9) with a new value of the `Sequence Code of Decade Fortune Co-ordinates' of `34'. Thus, the value of the `Sequence Code of Decade Fortune Co-ordinates' is changed from `38' to `34'. |
